Question

Your heating system is 45 percent energy efficient. A) What amount of energy would it consume to transform 9000 kWh into useful thermal energy for heating the house during the winter?

Answer 1

Let E be the total amount of energy that the heating system would consume in order to transform 9000kWh into useful thermal energy.

Since the efficiency of the system is 45%, then, 9000kWh is equal to 45% of E.

This means that 45% of the total energy consumed is transformed into useful thermal energy. Then:

`(E)/(100)=(9000kWh)/(45)`

Solve for E:

`E=(100)/(45)*9000kWh=20,000kWh`

Therefore, the total amount of energy consumed by the system would be 20,000kWh.