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Find the magnitude and direction (in degrees) of the vector: v= 〈-√2/2,-√2/2〉
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Find the magnitude and direction (in degrees) of the vector: v= 〈-√2/2,-√2/2〉

User Raugaral
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1 Answer

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Magnitude is sqrt ( -sqrt2/2 ^2 + -sqrt2/2 ^2)
= sqrt (0.5 + 0.5)
= 1
The vector is in the third quadrant and its tangent = 1 so the angle is 180 + 45
= 225 degrees


User Cederlof
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