Answer is: 8.24 kJ of heat is absorbed by the calorimeter.
ΔT= 27.08°C - 24.00°C.
ΔT = 3.08°C; temperature change of reaction.
m = 8.5 g; mass of methane.
cp= 2.677 kJ/°C, specific heat capacity of the bomb calorimeter.
Qcal = ΔT(methane) · cp(methane).
Qcal = 3.08°C · 2.677 kJ/°C.
Qcal = 8.245 kJ; amount of heat absorbed.