Question

Which substance is the reducing agent in this reaction?Cr2O72−+3HNO2+5H+→2Cr3++3NO3−+4H2O Express your answer as a chemical formula.

Answer 1

Step-by-step explanation:

According to this equation:

Cr2O72− + 3HNO2 + 5H+ → 2Cr3+ + 3NO3− + 4H2O

The half-reactions are:

Oxidation)

`3\text{ N}^(III)=>\text{ 3 N}^V+\text{ 6e}^(-1)`

Reduction)

`2\text{ Cr}^(VI)+\text{ 6e}^(-1)=>\text{ 2 Cr}^(III)`

HNO2 is the reducing agent

Cr2O7- is an oxidizing agent

Answer: HNO2 is the reducing agent

`3\text{ N}^(III)=>\text{ 3 N}^V+\text{ 6e}^(-1)`