Question

Write an equation of the line parallel to the one described by given equation that passes through the given point.

Parallel to y+x=3 through the point (−12,0)
please help me! thank you!

Answer 1

try going on desmos.com My math teacher showed it to us. it makes graphing a lot easier. Anyways. y=3-x, (-12[y intercept], 0). Now this means that your equation would be y=-12-x

hope this helps!!!

Answer 2

The equation of this line is y = -x - 12

Explanation:

In order to find the equation of the line, we first have to solve the first equation for y. Once we do that, we will have the slope.

y + x = 3

y = -x + 3

Now we can see the slope is -1. Since they are parallel lines, we know that the slope is also -1. Which means we can use the slope and the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 0 = -1(x - -12)

y = -1(x + 12)

y = -x - 12