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Calculate the amount of heat required for the evaporation of 105.0 g of water at 100.0 c

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To determine the amount of heat needed to evaporate a certain amount of water at its boiling point, we use the equation,

H = m(Hv)

where H is the heat, m is the mass (in grams), and Hv is the latent heat of vaporization. Substituting the known values,

H = (105 g)(540 cal/g)

H = 56700 cal

H = 56.7 kcal

Answer: 56.7 kcal
User Tim Schruben
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