Question

A large city in the ancient world was square-shaped. measured in miles, its area numerically exceeded its perimeter by about 132. find its dimensions. (round to the nearest tenth.

Answer 1

area = perimeter + 132.

Let each side of the city be x miles long, then:-

x^2 = 4x + 132
x^2 - 4x - 132 = 0

x = [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2

x = 13.66, -9.66 We ignore the negative

So the city has dimension of 13.66 * 13.66

13.7 * 13.7 to nearest 10th