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A lightbulb has an efficiency of 8.2%. How much light energy (not heat energy) is generated by the bulb every second if the bulb has a power of 21 W?

User Artahian
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2 Answers

4 votes

Answer:

1.72 J

Step-by-step explanation:

A P E X

User Shadowen
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The efficiency is the useful energy (or power) you get out of a system, divided by the energy (or power) you put in.
If the efficiency is 8.2%, that means you get 8.2% * 21 W = 1.72 W of useful power out.
Energy is just power multiplied by time, so 1.72 W * 1 s = 1.72 J.
User Tunguska
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