Factor by grouping 2u^3+3u^2-14u-21

asked May 27, 2018 14.5k views

3 votes

by Zalo

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4 votes

(2u³+3u²)-(14u+21)
u²(2u+3)-7(2u+3)
(u²-7)(2u+3)
(u+√7)(u-√7)(2u+3)

Saurabh Dhage answered May 29, 2018

8.7k points

2 votes

$\bf 2u^3+3u^2-14u-21\implies (2u^3+3u^2)-(14u+21) \\\\\\ u^2(2u+3)-7(2u+3)\implies \stackrel{\stackrel{common}{factor}}{(2u+3)}(u^2-7)$

PyMaster answered Jun 1, 2018

7.8k points

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