231k views
3 votes
Uche pumps gasoline at a rate of 18 L/min

What is Uche's pumping rate in mL/s ?

User Fguchelaar
by
6.5k points

2 Answers

6 votes
there are 1000 mL in a Liter and 60 seconds in a minute

18 L / min = 18,000 mL /min

so in mL/s the answer is 18000 / 60 = 300 mL/s Answer
User Jbpros
by
7.2k points
2 votes

Answer:


\frac{300\text{ ml}}{\text{ second}}

Explanation:

We have been given that Uche pumps gasoline at a rate of 18 L/min. We are asked to find Uche's pumping rate in mL/s.

To solve our given problem we need to convert our given rates.

1 liter = 1000 ml

1 minute = 60 seconds.

Upon


\text{Uche's pumping rate}=\frac{\text{18 L}}{\text{min}}* \frac{\text{1000 ml}}{\text{L}}* \frac{\text{1 min}}{\text{60 seconds}}


\text{Uche's pumping rate}=\frac{18*\text{1000 ml}}{\text{60 seconds}}


\text{Uche's pumping rate}=\frac{18,000\text{ ml}}{\text{60 seconds}}


\text{Uche's pumping rate}=\frac{300\text{ ml}}{\text{ second}}

Therefore, Uche's pumping rate in mL/s would be
\frac{300\text{ ml}}{\text{ second}}.

User Acarlow
by
6.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.