Question

What is the quotient [3y+2/3y] / [6y^2+4y/3y+2]

Answer 1

B

Explanation:

Answer 2

Answer:
`(3y+2)/(6y^2)`

Step-by-step explanation: Given rational expression :
`((3y+2)/(3y) )/((6y^2+4y)/(3y+2) )`.

Rewriting it in proper form.

`(3y+2)/(3y)` ÷
`(6y^2+4y)/(3y+2)`

Converting division sign into multiplication and flipping second fraction, we get

`(3y+2)/(3y)`×
`(3y+2)/(6y^2+4y)`

Factoring out 2y from
`6y^2+4y`

`6y^2+4y = 2y(3y+2)`

`(3y+2)/(3y)`×
`(3y+2)/(2y(3y+2))`

Crossing out common factors (3y+2) in second fraction, we get

=
`(3y+2)/(3y)`×
`(1)/(2y)`

=
`(3y+2)/(6y^2)`.