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Given ΔABC with A(–4, –2), B(4, 4), and C(18, –8), write the equation for the line containing median segment The term is line segment CP. in slope intercept form

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Here we want to find the equation of the line containing the median CP.

P, being the midpoint of AB can be found using the midpoint formula as:


\displaystyle{ P=( (-4+4)/(2) , (-2+4)/(2) )=(0, 1).


The slope m of the line through CP can be found by the slope formula using points C(18, -8) and P(0, 1):


\displaystyle{ m= (y_2-y_1)/(x_2-x_1)= (-8-1)/(18-0)= (-9)/(18)= (-1)/(2).


Now, we can write the equation of the line with slope -1/2, passing through
P(0, 1):


y-1= (-1)/(2)(x-0)\\\\y= -(1)/(2)x+1.


Answer:
y=-(1)/(2)x+1
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