Question

Jamal's friends toss 12 balls to him at the same time. Three balls are red, 3 are green, 3 are blue, and 3 are white. Jamal manages to catch 5 of the balls.What is the probability that he catches 2 red balls and 1 ball of each of the other colors?Enter your answer as percentage, expressed to the nearest tenth of a percent, like this: 42.2%

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

total balls = 12

red = 3

green = 3

blue = 3

white = 3

Step 02:

probability:

p (x) = favourable outcomes / total outcomes

p(red) = 3 / 12 = 1 / 4

p(green) = 3 / 12 = 1 / 4

p(blue) = 3 / 12 = 1 / 4

p(white) = 3 / 12 = 1 / 4

total probability:

`\text{total probability (5 balls) = (}(1)/(4)\cdot(1)/(4))\cdot(1)/(4)\cdot(1)/(4)\cdot(1)/(4)=(1)/(1024)`

total probability = 0.0009766 * 100% = 0.09766%

The answer is:

0.1%