Question

The number of pollinated flowers as a function of time in days can be represented by the function. f(x)=(3)x2 What is the average increase in the number of flowers pollinated per day between days 4 and 10?

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Answer 1

This is the correct answer! Sorry I am late also, but hope this helps other students! Also sorry for horrible handwriting.. lol! Have a nice day! And this really helpful for k12 users.

Answer 2

So in this case f(x) is number of pollinated flowers and x is the days. First you will need to determine the number of flowers pollinated at days 4 and 10 and the days in between.
f(4)= 3(4^2)= 3*16 = 48
f(5)= 3(5^2)= 3*25 =75
f(6)= 3(6^2)=3*36=108
f(7)= 3(7^2)=3*49=147
f(8)= 3(8^2)=3*64=192
f(9)= 3(9^2)= 3*81=243
f(10)= 3(10^2)=3*100=300
Now we need to find the average increase, so that will be the average of the differences between days
[(75-48)+(108-75)+(147-108)+(192-147)+(243-192)+(300-243)]/6
=(27+33+39+45+51+57)/6=42