Question

3) Castel and Gabriella are selling pies for a school fundraiser. Customers can buy apple pies and lemon meringue pies. Gabriella sold 6 apple pies and 4 lemon meringue pies for a total of $80. Gabriella sold 6 apple pies and 5 lemon meringue pies for a total of $94. What is the cost each of one apple pie and one lemon meringue pie?

Answer 1

Given:

Castel:

Amount of apples sold = 6

Amount of lemon sold = 4

Total = $80

Gabriella:

Amount of apple pies sold = 6

Amount of lemon sold = 5

Total = $94

Let's find the cost of one apple pie and one lemon menrigue pie.

Let x represent cost of one apple pie

Let y represent cost of one lemon meringue pie

From this situation, we have the system of equations:

6x + 4y = 80.............equation 1

6x + 5y = 94.............equation 2

Let's solve the system by elimination.

Multiply equation 1 by -1:

-1(6x + 4y) = -1(80)

-6x - 4y = -80

Add the two equations:

-6x - 4y = -80

6x + 5y = 94

___________

0 + y = 14

y = 14

Substitute 14 for y in either of the equations.

Take equation 2:

6x + 5(14) = 94

6x + 70 = 94

Subtract 70 from both sides:

6x + 70 - 70 = 94 - 70

6x = 24

Divide both sides by 6:

`\begin{gathered} (6x)/(6)=(24)/(6) \\ \\ x=4 \end{gathered}`

Thus, we have:

x = 4, y = 14

The cost of one apple pie is $4

The cost of one Lemon menringue is $14

ANSWER:

Cost of one apple pie = $4

Cost of one Lemon Menringue pie = $14