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A student in gym class swings from a rope and they are moving 5 m/s at the bottom of their swing. What is the height they reach above the floor before swinging back down? 1/2v^2=gh g = 9.8 m/s^2 A 2.55
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A student in gym class swings from a rope and they are moving 5 m/s at the bottom of their swing. What is the height they reach above the floor before swinging back down?

1/2v^2=gh g = 9.8 m/s^2
A 2.55 m
B. 1.28 m
c. 5m
D. 12.5 m​

User Akaliza
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1 Answer

10 votes

Answer:

A

Step-by-step explanation:

User DU Jiaen
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