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What is the total mass of 222rn remaining in an original 160 milligram sample?
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What is the total mass of 222rn remaining in an original 160 milligram sample?

User Lsimmons
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1 Answer

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n x / 160 = - k x 19.1
rate of reaction is required
222Rn has a half-life of 3.8235 d.
160 Ă— .5^( 19.1/3.8235 ) = 5.0 mg
5.0 mg is the total mass of 222Rn remaining in an original 160-milligram sample of 222Rn.
User Stefan Svrkota
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