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If the child pulls with a force of 19 n for 15.0 m , and the handle of the wagon is inclined at an angle of 25 ∘ above the horizontal, how much work does the child do on the wagon?
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If the child pulls with a force of 19 n for 15.0 m , and the handle of the wagon is inclined at an angle of 25 ∘ above the horizontal, how much work does the child do on the wagon?

User Zhartaunik
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1 Answer

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The solution for this problem is we will be using the formula for work which is:
Work = Fs, where F is the component of the force in the direction of motion
Horizontal component of force = F = (19 N)(cos 25) = (19)(0.906)
Fs = (190)(0.906) = 172.14 J
User Rashard
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