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A certain species of bacteria grows at a rate of 48% per day. There are 500 initially, therefore the equation is y = 500(1.48)t. Write an equation for the amount of bacteria in …

A certain species of bacteria grows at a rate of 48% per day. There are 500 initially, therefore the equation is y = 500(1.48)t. Write an equation for the amount of bacteria in …
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A certain species of bacteria grows at a rate of 48% per day. There are 500 initially, therefore the equation is y = 500(1.48)t. Write an equation for the amount of bacteria in terms of hours.

User Andy Muth
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2 Answers

1 vote
someone help me please
User Sajadre
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4 votes

Answer:y=500(1.016)*24t

Explanation:

User Praytic
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