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In parallelogram ABCD , AE=x2−8 and CE=2x .

What is AC?

4

8

16

24

In parallelogram ABCD , AE=x2−8 and CE=2x . What is AC? 4 8 16 24-example-1
User Zounadire
by
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2 Answers

4 votes

Answer:

16

Explanation:


In parallelogram ABCD , AE=x2−8 and CE=2x . What is AC? 4 8 16 24-example-1
User Jaysoncopes
by
7.1k points
4 votes
Answer: 8

The point E in the parallelogram is located at the crossing point of the diagonal line. It can be concluded that the distance of AE is equal to CE, or equal to 1/2 AC. Then you can get three equation like this:
AE=CE
AE=x^2−8
CE=2x .

Using these equation you can find the value of x
AE= CE
x^2−8 = 2x
x^2−2x-8 = 0
(x- 4) (x+2)
x1= 4 x2= -2

Excluding the minus result, you can get that AE= CE= 4
Then AC would be:
AC= AE+CE
AC= 4 + 4= 8
User Imma
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6.8k points