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Finding the vertex focus directrix and acts of symmetry of the parabola

Finding the vertex focus directrix and acts of symmetry of the parabola-example-1
User Kakey
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1 Answer

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Answer:

Step-by-step explanation:

a) Here, we want to find the equation of the directrix of the parabola.

We have that as follows:


(x-2)\placeholder{⬚}^2=\text{ -\lparen y+1\rparen}

We compare the above with the following:


(x-h)\placeholder{⬚}^2=4p(y-k)

what we have here will be:

h = 2, k = -1 and p = -1/4

Directrix:

y = k-p

y = -1 + 1/4 = -3/4

b) Vertex

We have the vertex as (h,k)


(2,-1)

c) Focus

User Tom Lilletveit
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