Answer:
Solution: (4, -4)
Step-by-step explanation:
The system of equations is
y = -(1/2)x -2
y = -(3/2)x + 2
The linear equations have the form y = mx + b, so m is the number beside x and b is the constant number, so for each equation, we get:
y = -(1/2)x -2
b = -2
m = -1/2
y = -(3/2)x + 2
b = 2
m = -3/2
Then, to find the solution, we need to graph each equation, so we need to identify two points for each equation.
For y = -(1/2)x -2
If x = 0
y = (-1/2)(0) - 2 = -2
If x = 2
y = (-1/2)(2) - 2 = -1 - 2 = -3
For y = -(3/2)x + 2
If x = 0
y = (-3/2)(0) + 2 = 2
If x = 2
y = (-3/2)(2) + 2 = -3 + 2 = -1
So, we will use the points (0, -2) and (2, -3) to graph y = -(1/2)x -2 and the points (0, 2) ad (2, -1) to graph y = -(3/2)x + 2. Then, the graph of the system is
Therefore, the solution of the system is (4, -4) because it is the intersection point of the lines.