Answer-
SAS could be used to prove that ΔACP ≅ ΔBCP
Solution-
In triangle ACP and triangle BCP,
- ∠APC ≅ ∠BPC (Given that they both are right angles)
- AP = BP (Given)
- CP is common to both the triangles
So, according to the SAS (Side-Angle-Side) congruency ΔACP≅ΔBCP
Therefore, SAS could be used to prove that ΔACP ≅ ΔBCP