So!
This is a system of equations. So there are two ways to solve the problem: elimination or substitution.
Now...I'll use the elimination method, where you add the equations in such a way that one of the variables cancel.
I choose to eliminate"y". the coefficients are 0.2 and 1.2....uh oh....they don't cancel....what do I do?
multiply both numbers by the l.c.m. (lowest common multiple), and that's 1.2.
multiply the whole first equation by 6 to get "-9.6x+1.2y=52.8 "
and multiply the whole second equation by 1 to get "0.5x+1.2y=-7.8"
So "y" has the same coefficient, but we need them to cancel, remember?
Make one of the equations negative.
Using the second one, multiply by d - 1: -0.5x-1.2y = 60.6
Now we can add the equations!
Add the "x's" and the "y's" and constants together.
The result is the following: -10.1x = 16.6
x = -6
Now take the value of "x" and put it into one of the equations.
Let's use the first one: -1.6x+0.2y=8.8
-1.6(-6) + 0.2y = 8.8
9.6 + 0.2y = 8.8
0.2y = -0.8
y = -4
Therefore, the answers are "x = -6" and "y = -4".
Hope this helps.