Question

A 0.420 M Ca(OH)2 solution was prepared by dissolving 64.0 grams of Ca(OH)2 in enough water. What is the total volume of the solution formed? (4 points) a1.07 liters b1.23 liters c2.05 liters d2.18 liters

Answer 1

the volume of the solution is 2.05 liters

Step-by-step explanation

Given that;

The concentration of Ca(OH)2 is 0.420M

The grams of Ca(OH)2 is 64.0 grams

Follow the steps below to find the volume of the solution

Step 1; Calculate the number of moles of Ca(OH)2 using the below formula

`\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}`

Recall, that the molar mass of Ca(OH)2 is 74.093 g/mol

`\begin{gathered} \text{ mole = }\frac{\text{ 64}}{74.093} \\ \text{ mole = 0.864 mole} \end{gathered}`

Step 2; Find the volume of the solution in liters using the below formula

`\text{ Molarity = }\frac{\text{ moles of the solute}}{\text{ liters of solution}}`
`\begin{gathered} \text{ 0.420 = }\frac{\text{ 0.864}}{\text{ V}} \\ \text{ cross multiply} \\ \text{ 0.420V = 0.864} \\ \text{ Divide both sides by 0.420} \\ \text{ }\frac{\text{ 0.420V}}{0.420}\text{ = }\frac{\text{ 0.864}}{\text{ 0.420}} \\ \text{ V = 2.05 Liters} \end{gathered}`

Therefore, the volume of the solution is 2.05 liters