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What is the largest of 3 consecutive even integers such that twice the sum of the larger two is 4 less than 5 times the smallest? C. B. S 20 D. 24 A. 6

User James Douglas
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1 Answer

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1) Consecutive even numbers are unit bigger than the prior one. Hence

2k

2k+1

2k+ 2

2[(2k+2)+(2k+1)]=4-5(2k)

2[4k+3]=4-10k

8k+6=4-10k

8k+10k=4-6

18k=-2

k=-2/18

k=-1/9

2k+2

User Mauritz Hansen
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