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What is the radical form of each of the given expressions?

Drag the answer into the box to match each expression.

Choices in photo below.

What is the radical form of each of the given expressions? Drag the answer into the-example-1

2 Answers

7 votes

Answer:
5^{(2)/(3)}= \sqrt[3]{5^2}


5^{(1)/(2)}= √(5)


3^{(2)/(5)}= \sqrt[5]{3^2}


3^{(5)/(2)}= √(3^5)


Step-by-step explanation: According to the rule of exponent of radical form:


a^{(m)/(n) } = \sqrt[n]{a^m}.

Let us apply same rule in first number


5^{(2)/(3)}= \sqrt[3]{5^2}


5^{(1)/(2)}= √(5)


3^{(2)/(5)}= \sqrt[5]{3^2}


3^{(5)/(2)}= √(3^5)

Note: When we don't have any number on the top of radical, there 2 is understood.



What is the radical form of each of the given expressions? Drag the answer into the-example-1
User Baxbear
by
6.5k points
4 votes
The main rule to apply here is:

(i)
\displaystyle{ a^ {\displaystyle{ ((b)/(c))} }= \displaystyle{ \sqrt[c]{a^b}

(ii)If c=2, then we write the following
\displaystyle{ a^ {\displaystyle{ ((b)/(2))} }= \displaystyle{ √(a^b).


According to these rules:


\displaystyle{ 5^ {\displaystyle{ ((2)/(3))} }= \displaystyle{ \sqrt[3]{5^2}.


\displaystyle{ 5^ {\displaystyle{ ((1)/(2))} }= \displaystyle{ √(5^1)=\displaystyle{ √(5).


\displaystyle{ 3^ {\displaystyle{ ((2)/(5))} }= \displaystyle{ \sqrt[5]{3^2}.


\displaystyle{ 3^ {\displaystyle{ ((5)/(2))} }= \displaystyle{ √(3^5).
User Dbmikus
by
6.8k points