Question

A man is known to speak truth 2 out of 3 times. he throws a die and reports that number obtained is a four. find the probability that the number obtained is actually a four.

Answer 1

Ok so in this problem we need to multiply the probability of both events together to find how likely it is that the die actually rolled a 4.

`(2)/(3)` is the amount of times he speaks the truth, so we multiply that by
`(1)/(6)` for the die, because the die has 6 sides

`(1)/(6)` ×
`(2)/(3)` =
`(2)/(18)`
Simplify to get
`(1)/(9)`. Hope this helped!