Question

The Palace of Peace and Accord in Astana, Kazakhstan, was built in 2006. The building has a square right pyramid structure. The length of a side of the square base is 62 m, and the vertical height of the pyramid is also 62 m. What is the height, h, of one of the triangular faces? Round your answer to the nearest tenth.

Answer 1

Answer: 69.32 m

Explanation:

Since, slant height of the square right pyramid,
`s^2=√(h^2+(1/4) a^2)`

where,

h = height of the pyramid

a= side of the square

And, here h= 62 m and a= 62 m

Therefore,
`s^2=√(62^2+(1/4) 62^2)`

⇒
`s^2=√(3844+961)`

⇒
`s^2=√(4805)`

⇒s=69.3181073025≈ 69.32 m

Thus, the height of triangular face = 69.32 ( approx)