Question

A ball is thrown horizontally at a speed of 24 m/s from the top of a cliff. if the ball hits the ground 4.0 s later, approximately how high is the cliff?

Answer 1

To determine the height of the cliff, we can use the equations of motion to analyze the projectile motion of the ball.

Step-by-step explanation:

To determine the height of the cliff, we can use the equations of motion to analyze the projectile motion of the ball. Since the ball is thrown horizontally, the initial vertical velocity is zero. We can use the equation h = 1/2gt^2 to find the height of the cliff.

In this case, the time, 't', is given as 4.0 s and the acceleration due to gravity, 'g', is approximately 9.8 m/s^2. Plugging these values into the equation, we get:

h = 1/2(9.8 m/s^2)(4.0 s)^2 = 78.4 m

Therefore, the height of the cliff is approximately 78.4 meters

Answer 2

144 m 24 divided by 4 = 6 24 x 6 = 144