80.5k views
4 votes
A jet travels 1743mi against the wind in 3 hours and 2103mi with the wind in the same amount of time. What is the rate of the jet in still air and what is the rate of the wind?

1 Answer

6 votes
recall your d = rt, distance = rate * time.

bear in mind that, say if the still air speed of the plane is say "p", and the wind has a speed of say "w", when the plane is going with the wind is not really going at "p" mph, is going at "p + w" mph.

likewise, when the plane is going against the wind, is not going "p" mph either, is really going "p - w", because the wind is eroding speed from it.


\bf \begin{array}{lccclll} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ &------&------&------\\ \textit{against the wind}&1743&p-w&3\\ \textit{with wind}&2103&p+2&3 \end{array} \\\\\\ \begin{cases} 1743=3(p-w)\\ (1743)/(3)=p-w\\ 581=p-w\\ \boxed{w}=p-581\\ --------\\ 2103=3(p+w)\\ (2103)/(3)=p+w\\ 701=p+w \end{cases} \\\\\\ 701=p+\left( \boxed{p-581} \right)\implies 701+581=p+p \\\\\\ 1282=2p\implies \cfrac{1282}{2}=p\implies 641=p

so, what's the speed of the wind anyway? well, w = p - 581.
User Lancew
by
8.1k points

No related questions found