Heyo! ;D
So, analyzing the question above, the internal angles of ΔPQT are as follows:
∠TPQ
∠PQT ≅ ∠SQR
∠QTP
The internal angles of ΔRSQ would be as follows:
∠SRQ
∠SRQ ≅ ∠PQT
∠QSR
Hence, ∠PQT would be the common angle of ∠PQT and ∠RSQ. Hope this helps!