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1/3(6x+24)-20 < -1/2(6x-36)

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Hi there!
The question here gives us an inequality, and it tells us to solve for x.

(1)/(3) (6x+24)-20 \ \textless \ - (1)/(2) (6x-36)
First, use the distributive property to simplify both sides of the equation.

2x+8-20\ \textless \ -3x+18
Now, on the left side of the inequality, combine like terms.

2x-12\ \textless \ -3x+18
Add 12 to both sides.

2x\ \textless \ -3x+30
Add 3x to both sides.

5x\ \textless \ 30
Divide 5 from both sides.

x\ \textless \ 6
Therefore, the solution to the inequality is anything less than 6, or x < 6. Hope this helped!
User Juvi
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