Question

Evaluate the permutation. 6 P 2

Answer 1

`\bf _nP_r=\cfrac{n!}{(n-r)!}\qquad \qquad \qquad _6P_2=\cfrac{6!}{(6-2)!}`

Answer 2

`P(6,2)=30`

Explanation:

We are asked to evaluate the permutation
`_(2)^(6)\textrm{P}`.

We will use permutations formula to solve our given problem.

`P(n,r)=(n!)/((n-r)!)`, where,

n = Total number of items,

r = Number of items taken at a time.

Upon substituting our given values we will get,

`P(6,2)=(6!)/((6-2)!)`

`P(6,2)=(6!)/(4!)`

`P(6,2)=(6*5*4!)/(4!)`

`P(6,2)=6*5`

`P(6,2)=30`

Therefore, the answer would be 30.