Answer:
<QRP = 48.2°
Explanation:
Given:
PR = 18 cm
QR = 12 cm
Required:
<QRP = angle R
Solution:
Reference angle = <R (<QRP)
Adjacent side length = 12 cm
Hypotenuse = 18 cm
Thus:
Cos (R) = 12/18
cos (R) = 0.6667
<QRP = 48.2° (nearest tenth)
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