Question

Write the equation of a line that is perpendicular to the line y = x – 5 and contains the

point (-4, 13)?

Answer 1

y = -x + 9

Explanation:

Here, we want to write the equation of a line

mathematically, if two lines are perpendicular, the product of their slopes is -1

Comparing the given equation with the general form of;

y = mx + b

where m is the slope and b is the y-intercept, we can see that the slope value is 1

So the slope of the second line will be;

-1/1 = -1

now we want to write the equation of a line that has a slope of -1 and passes through the point (-4, 13)

we use the point-slope form here

That will be;

y-y1 = m(x-x1)

y-13 = -1(x+ 4)

y-13 = -x - 4

y = -x -4 + 13

y = -x + 9