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Factor 6x4 – 5x2 + 12x2 – 10 by grouping. What is the resulting expression? (6x + 5)(x2 – 2) (6x – 5)(x2 + 2) (6x2 + 5)(x2 – 2) (6x2 – 5)(x2 + 2)

User Kenitech
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2 Answers

5 votes

x^(2)(6
x^(2) - 5) + 2(6
x^(2) - 5
(6
x^(2) - 5) (
x^(2) + 2)


Answer: D).
User Mycroft Canner
by
7.8k points
4 votes

Answer: The correct option is (D)
(6x^2-5)](x^2+2).

Step-by-step explanation: We are given to factorize the following polynomial expression of degree 4 by grouping :


P(x)=6x^4-5x^2+12x^2-10.

Let x² = y, then the given expression becomes


P(x)\\\\=6x^4-5x^2+12x^2-10\\\\=6y^2-5y+12y-10\\\\=y(6y-5)+2(6y-5)\\\\=(6y-5)(y+2)\\\\=(6x^2-5)(x^2+2).

Thus, the required factorized form is
(6x^2-5)(x^2+2).

Option (D) is CORRECT.

User Andersfylling
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