Question

A sample of argon gas has a volume of 735 mL at a pressure of 1.20 atm and a temperature of 112 ∘C. What is the final volume of the gas, in milliliters, when the pressure and temperature of the gas sample are changed to the following, if the amount of gas does not change?660 mmHg and 274 K.65 atm and 77 ∘C

Answer 1

For this question we will make use of the Combined Gas Law:

`\begin{gathered} (P_1V_1)/(T_1)=(P_2V_2)/(T_2) \\ P_1:initial\text{ }pressure\text{ }(atm) \\ V_1:initial\text{ }volume\text{ }(mL) \\ T_1:initial\text{ }temperature\text{ }(K) \\ P_2:final\text{ }temperature\text{ }(atm) \\ V_2:final\text{ }volume\text{ }(mL) \\ T_2:final\text{ }temperature\text{ }(K) \end{gathered}`

Answer to part A)

Given:

P2:660 mmHg

T2: