Question

Using xn+1 = 1 -(3/x^2)
with x0 = -2.5
Find the values of X1, X2 and X3 using iteration​

Answer 1

= 0.52, -10.094 and 0.9705561461

Explanation:

If you input this equation into a calculator while using brackets around
`x`n, you should get these values above. Hope that helps!

Answer 2

The values of
`x_(1)`,
`x_(2)` and
`x_(3)` are 0.52, -10.094 and 0.971.

Explanation:

Let
`x_(n+1) = 1-(3)/(x_(n)^(2))` be the recurrence formula and
`x_(o) = -2.5`. The first values of this recurrence are, respectively:

`x_(1)`:

`x_(1) = 1 - (3)/(x_(o)^(2))`

`x_(1) = 1-(3)/((-2.5)^(2))`

`x_(1) = 0.52`

`x_(2)`:

`x_(2) = 1-(3)/(x_(1)^(2))`

`x_(2) = 1-(3)/(0.52^(2))`

`x_(2) = -10.094`

`x_(3)`:

`x_(3) = 1-(3)/(x_(2)^(2))`

`x_(3) = 1 - (3)/((-10.094)^(2))`

`x_(3) = 0.971`

The values of
`x_(1)`,
`x_(2)` and
`x_(3)` are 0.52, -10.094 and 0.971.