Question

THE THREE SIDES OF A TRIANGULAR LOT

ARE MEASURED TO BE APPROXIMATELY 100.52
FT, 15.321 FT AND 143.250 FT LONG. FIND THE
APPROXIMATE PERIMETER OF THE LOT​

Answer 1

259.09 feet

Explanation:

Given that,

The three sides of a triangular lot are measured to be 100.52 ft, 15.321 ft and 143.250 ft.

We need to find the perimeter of the lot.

We know that,

Perimeter = sum of all sides

P = 100.52 + 15.321 + 143.250

P = 259.09 feet

So, the required perimeter of the lot is 259.09 feet.