Solution
If we have a polynomial odf degree 3 it must have 3 roots
And one of then should be real the answer is true
And the correct choice is:
a. Yes, because complex roots must appear in conjugate pairs, leaving one root real.
Since we have two possible options:
1) (x-i)(x+i) (x-a) with 2 factors conjugate and 1 root real a and two other complex numebrs
2) (x-a)(x-b)(x-c) with 3 real roots a,b and c
So then we must have at least one root assuming that the coeffcients of the polynomial are not complex