Question

A bobsleigh with four people on board has a total mass of 610 kg. How fast is the sleigh moving if it has a kinetic energy of 40.0 kJ?

Answer 1

40 kj to j is 40000 j, we know that KE=(1/2)mv², therefore v=√2K/m, therefore v=√2×40000j/610kg, v=11.5 m/s

Answer 2

v= 11.45
`(m)/(s)`

Step-by-step explanation:

kinetic equation

`E_(k) = (1)/(2) * m * v^(2)`,
`E_(k) = 40.0 k J` ,
`m=610 kg`

`E_(k)*2 = m * v^(2)\\(2*E_(k))/(m) = v^(2) \\v =  \sqrt{(2*E_(k))/(m) } \\v =  \sqrt{(2*40x10^(3) (kg*m^(2) )/(s^(2))  )/(610 kg) } = \sqrt{131.147 (m^(2))/(s^(2)) } \\`

`v= 11.45 (m)/(s)`