Question

Find the Area of the figure below, composed of a parallelogram and two semicircles. Round to the nearest tenths place.

See the picture


Please

Answer 1

100.3

Explanation:

Area of parallelogram = 10 * 5 = 50 (As to find the area of a parallelogram, you would need to multiply the height and base: just like a rectangle)

We now have to work out the area of the two semi-circles. Both semi-circles have the same diameter which is 8, which means the semi circles are of the same size. Therefore we would just need to work out the area of 1 semi-circle and apply it to the second semi-circle (if that makes sense).

Area of semi-circle = 1/2(πr2 ) --> The '2' is supposed to be squared of r

radius = 8/2 = 4

1/2 (π*4*4)

Put that in calculator and should equal = 8π (Area of 1 semi-circle)

Area of 2 semi-circles = 8π + 8π = 16π

Total Area = (Area of parallelogram) + (Area of 2 semi-circles)

TA = 50 + 16π

Total Area (Nearest tenths place): 100.3

Hope this helps :)

Answer 2

• 100.2 square units

Explanation:

The figure comprises of two semicircles and a parallelogram.

The two semicircles add to one full circle.

Area of circle:

• A = πr²
• A = 3.14*(8/2)² = 3.14*16 = 50.2 square units (rounded to the nearest tenth)

Area of parallelogram:

• A = ah
• A = 10*5 = 50 square units

Total area is the sum of the two:

• 50.2 + 50 = 100.2 square units