Question

How many grams of N are in 89.0 g of NH4NO3

Answer 1

To find how many grams of nitrogen are in 89.0 g of NH4NO3, one must calculate the moles of NH4NO3 and then use the proportion of nitrogen's mass in the molecule, which results in 31.14 grams of nitrogen.

Step-by-step explanation:

To calculate the number of grams of nitrogen (N) in 89.0 g of NH4NO3, we need to understand the composition of the molecule and the molecular mass of the components. Ammonium nitrate (NH4NO3) consists of two nitrogen atoms, which we can calculate as a fraction of the overall molar mass. The molar mass of NH4NO3 is 80.06 g/mol. Nitrogen's molar mass (N) is 14.01 g/mol, and since we have two N atoms in NH4NO3, we get 28.02 g/mol from nitrogen.

To find the amount of nitrogen in the sample, we perform the following calculation:

1. Calculate the moles of NH4NO3 in 89.0 g: (89.0 g) / (80.06 g/mol) = 1.111 moles of NH4NO3.
2. Calculate the mass of N from the moles of NH4NO3: (1.111 moles) × (28.02 g/mol) = 31.14 g of N.

Therefore, there are 31.14 grams of nitrogen in 89.0 grams of NH4NO3.

Answer 2

Step 1;calculate the molar mass of NH4N03
molar mass of different element
N=14
H=1
O=16
therefore molar mass of NH4NO3 is 14+4+14+48= 80g/mol
step 2:find the molar mass of N present in NH4NO3
That is 14+14 =28g/mol
the mass is therefore
{(28g/mol/80g/mol) x 89g} =31.15g