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In a bag of 32 MnM's, there are 4 orange, 7 yellow, 6 green, 6 brown and 5 red and 4 blue. Find the probability that a blue is chosen, replaced and then a green is chosen…
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In a bag of 32 MnM's, there are 4 orange, 7 yellow, 6 green, 6 brown and 5 red and 4 blue. Find the probability that a blue is chosen, replaced and then a green is chosen…
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Aug 16, 2022
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In a bag of 32 MnM's, there are 4 orange, 7 yellow, 6 green, 6 brown and 5 red and 4 blue. Find the probability that a blue is chosen, replaced and then a green is chosen
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Answer:
p(B) = 4/32 = 1/8
p(G) = 6/32 = 3/16
LiveSource
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Aug 22, 2022
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