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In a bag of 32 MnM's, there are 4 orange, 7 yellow, 6 green, 6 brown and 5 red and 4 blue. Find the probability that a blue is chosen, replaced and then a green is chosen
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In a bag of 32 MnM's, there are 4 orange, 7 yellow, 6 green, 6 brown and 5 red and 4 blue. Find the probability that a blue is chosen, replaced and then a green is chosen

User Filipe Spindola
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1 Answer

5 votes

Answer:

p(B) = 4/32 = 1/8

p(G) = 6/32 = 3/16

User LiveSource
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