Question

*** TIMED ***

given that A=16 degrees , B=25 degrees and c=28, solve triangle ABC. Round to the nearest hundredth.

A) C= 139 degrees , b= 18.04 , a= 11.76
B) C= 41 degrees , b= 19.93 , a= 30.94
C) C= 139 degrees , b= 17.76 , a= 18.01
D) C= 41 degrees , b= 11.76 , a= 18.04

Answer 1

Answer is A.
c=139
b=18.04
a=11.76

Answer 2

Explanation:

Given are two angles and one side for triangle ABC. We have to solve for the triangle for unknown sides and angles to the nearest hundredth

Angle C =180-(A+B) = 180-(25+16) = 139

a = c·sin(A)/sin(C) =

=28sin16/sin139 = 11.76395

b = c·sin(B)/sin(C) = 18.03696

Round off to nearest 100th we get

a = 11.76 and b = 18.04 and angle C = 139 degrees.

Here there is only one solution and the solution is option A