Question

Btw this is not a test it’s homework on schoolagy

Answer 1

A standard deck contains 52 cards; without all the aces and twos, it would have 52-8=44 cards in total.

a) There are 13 heart cards in a normal deck; in this one, there are 13-2=11 heart cards; therefore,

`\begin{gathered} P(heart)=(11)/(44)=(1)/(4) \\ \Rightarrow P(heart)=(1)/(4) \end{gathered}`

The answer to part a) is P(heart)=1/4.

b) Half of the cards in a standard deck are black; since we removed 4 red cards and 4 black cards,

`P(black)=(22)/(44)=(1)/(2)`

P(black)=1/2

c) There are 12 face cards in a normal deck and none of them was removed; thus,

`P(face_{})=(12)/(44)=(3)/(11)`

P(face card)=3/11

d) In general, if A is an event,

`P(notA)=1-P(A)`

Therefore, in our case,

`\begin{gathered} P(notHeart)=1-P(heart)=1-(1)/(4)=(3)/(4) \\ \Rightarrow P(notHeart)=(3)/(4) \end{gathered}`

P(not heart)=3/4