Question

The radiation emitted from a star has a maximum intensity at a wavelength of 300 nm. what is the likely temperature of this star?

Answer 1

Here we can use Wien's Displacement Law to calculate the temperature. The formula is given as.

`peak \: wavelength = (wiens \: constant)/(temperature)`
We can rewrite that as

`temperature = (wiens \: constant)/(peak \: wavelength)`
The Wien constant is given as [K*m] (Kelvin*meter)

`2.897 * {10}^( - 3)`
So we convert our wavelength of 300 nm to m.

`3 * {10}^( - 7)`
Combine it all

`temperature = \frac{2.897 * {10}^( - 3) }{300 * {10}^( - 7) } = 9657`
The temperature is 9657 Kelvin