Question

-2 5/6 ÷ 3/51
please, please help !! thank you

Answer 1

Hello I hope I can be of assistance!

First..

`\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions} \ \textgreater \ (\left(-(17)/(6)\right))/((3)/(51))`


`\mathrm{Apply\:the\:fraction\:rule}:\ (-a)/(b)=-(a)/(b) \ \textgreater \ -((17)/(6))/((3)/(51))`


`\mathrm{Divide\:fractions}:\ ((a)/(b))/((c)/(d))=(a\cdot \:d)/(b\cdot \:c) \ \textgreater \ -(17\cdot \:51)/(6\cdot \:3)`


`\mathrm{Multiply\:the\:numbers:}\:6\cdot \:3=18 \ \textgreater \ -(17\cdot \:51)/(18)`


`\mathrm{Multiply\:the\:numbers:}\:17\cdot \:51=867 \ \textgreater \ -(867)/(18)`


`\mathrm{Cancel\:the\:common\:factor:}\:3 \ \textgreater \ -(289)/(6)`

Finally...

`\mathrm{Convert\:improper\:fractions\:to\:mixed\:numbers} \ \textgreater \ -48(1)/(6)`

Hope this helps!