Question

Hello hope all is well with you. Can you check to see if I did this right please.

Answer 1

Given data

9 17 5 5 33 13 1

From the given data

Maximum value Max = 33

Minimum value Min = 1

The mode of the data is the number that appears most or the most occurring number in the set.

The mode of the data = 5

To find the median, arrange the numbers in ascending or descending order of values.

1 5 5 9 13 17 33

The median = 9

The range of the data is the difference between the maximum and the minimum number in the data.

Range = 33 - 1 = 32

Mean is the sum of the numbers divided by the total number of numbers.

Q1 is the first quartile

`\begin{gathered} \text{Position of the quartile = }(1)/(4)(n+1)^(th) \\ \text{= }(1)/(4)(7+1)^(th) \\ =2^(th) \\ \text{ From 1 5 5 9 13 17 33} \\ Q1\text{ = 5} \end{gathered}`

Q3 is the third quartile

`\begin{gathered} \text{Position = }(3)/(4)(n+1)^(th) \\ =\text{ }(3)/(4)(7+1)^(th) \\ =6^(th) \\ Q3=17^{} \end{gathered}`

Interquartile range IQR = Q3 - Q1 = 17 - 5 = 12